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For example, the orbit of each planet in the solar system is approximately an ellipse with the Sun at one focus point (more precisely, the focus is the barycenter of the Sun–planet pair). The same is true for moons orbiting planets and all other systems of two astronomical bodies.

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String.fromCharCode () cannot return supplementary characters (i.e. code points 0x010000 – 0x10FFFF) by specifying their code point. Instead, it requires the UTF-16 surrogate pair in order to return a supplementary character: String.fromCharCode(0xD83C, 0xDF03); String.fromCharCode(55356, 57091); String.fromCodePoint (), on the other hand, can return 4-byte supplementary characters, as well as the more common 2-byte BMP characters, by specifying their code point (which is equivalent to the ...

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local WD, HT, NUM_POINTS = 256, 256, 16 local COLOR = { normal = '#000', closest = '#f00' } local RADIUS = 5 math.randomseed(os.time()) local P = {} for _ = 1, NUM_POINTS do P[#P+1] = { x = RADIUS + (WD - 2*RADIUS) * math.random(), y = RADIUS + (HT - 2*RADIUS) * math.random() } end -- Find closest pair, using naive algorithm. local closest_a, closest_b local min_dist for i, p in ipairs(P) do for j, q in ipairs(P) do if i ~= j then local dist = math.sqrt((p.x - q.x)^2 + (p.y - q.y)^2) if not ...

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How to ﬁnd closest pair with one point in each side? Find closest pair with one point in each side, assuming that distance < δ. ・Observation: only need to consider points within δ of line L. ・ ・ 2